Q&A on Gas Laws and Properties Batch 1: Basic Concept of Gases and Properties Q1: What is the state of matter in which inter-particle attraction is weak and inter-particle space is large?A1: The gaseous state is the state of matter where inter-particle attraction is weak, and inter-particle space is so large that the particles …
Master Triangles in 30 Minutes: A Quick Guide for CBSE Class 10 Students Q&A Style Revision 1. What is the Pythagoras Theorem? The Pythagoras Theorem states: In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Mathematically: (c^2 = a^2 + b^2), where …
CBSE Class 10 Triangles: Key Theorems & Problems Explained in 30 Minutes Read More »
Master Coordinate Geometry in 30 Minutes: A Quick Guide for CBSE Class 10 Students Q&A Style Revision 1. What is the Distance Formula in Coordinate Geometry? The distance between two points ((x_1, y_1)) and ((x_2, y_2)) is given by: (d = sqrt{(x_2 – x_1)^2 + (y_2 – y_1)^2}) 2. How do you calculate the Midpoint …
CBSE Class 10 Coordinate Geometry: Key Formulas & Problems in 30 Minutes Read More »
Master Probability in 30 Minutes: A Quick Guide for CBSE Class 10 Students Q&A Style Revision 1. What is Probability? Probability is the measure of how likely an event is to occur. It is expressed as a number between 0 and 1, where 0 means the event cannot happen, and 1 means the event is …
CBSE Class 10 Probability: Master Key Concepts & Problems in 30 Minutes Read More »
Master Statistics in 30 Minutes: A Quick Guide for CBSE Class 10 Students Q&A Style Revision 1. What is the formula for calculating the Mean (Direct Method)? The formula is: Mean ((bar{x})) = (frac{sum f_i x_i}{sum f_i}) 2. How do you calculate the Mean using the Assumed Mean Method? The formula is: (bar{x} = A …
CBSE Class 10 Statistics: Master Key Formulas & Problems in 30 Minutes Read More »
Saponification and Cleansing Agents: Detailed Guide Understanding Saponification: The Chemistry of Soap-Making Saponification is a vital chemical process where fats or oils (esters of fatty acids) react with a strong base like sodium hydroxide (NaOH) to create soap and glycerol. This reaction forms the backbone of traditional soap-making. General Equation for Saponification: Fat/Oil (Ester) + …
Saponification Explained: Soap vs. Detergent, Cleansing Action, and Key Differences Read More »
Velocity-Time Graph Question 2 The graph below shows the motion of a cyclist over a period of 12 seconds. Graph Description: The cyclist starts at a velocity of 2 m/s and accelerates uniformly to 12 m/s in the first 4 seconds. From 4 seconds to 8 seconds, the cyclist maintains a constant velocity of 12 …
Velocity-Time Graph Analysis: Cyclist Motion Explained with Solutions Read More »
Velocity-Time Graph Questions 1. Sketch the velocity-time graph based on the description provided. The graph should show: Acceleration from 0-5 seconds (0 to 10 m/s). Constant velocity from 5-8 seconds (10 m/s). Deceleration from 8-10 seconds (10 m/s to 0). Coordinates for the graph: Time (s) Velocity (m/s) 0 0 1 2 2 4 3 …
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Time and Motion Problems – Set 3 1. A bus travels 150 km in 2 hours 30 minutes. Calculate its speed in km/h. Speed = Distance / Time [ text{Time} = 2 , text{hours} + frac{30 , text{minutes}}{60} = 2.5 , text{hours} ] [ text{Speed} = frac{150 , text{km}}{2.5 , text{hours}} = 60 , text{km/h} …
time and Motion Problems: 12 Solved Examples with Detailed Explanations (Set 9) Read More »
Time and Motion Problems – Set 2 1. A car moves at a speed of 80 km/h for 4 hours. Calculate the distance covered. Distance = Speed × Time [ text{Distance} = 80 , text{km/h} times 4 , text{hours} = 320 , text{km} ] 2. A cyclist travels 18 km in 45 minutes. Find his …
12 Practical Time and Motion Problems with Step-by-Step Solutions (Set 8) Read More »
