Numerical Questions and Solutions 1. A car is running at a speed of 60 km/h. How much time will it take to cover a distance of 27 km? Time = Distance / Speed = 27 km / 60 km/h = 0.45 hours or 27 minutes. 2. Reema observes her wall clock’s pendulum completes 15 oscillations …
Numerical Questions and Solutions 1. A car covers 90 km in 1.5 hours. What is its speed in km/h? Speed = Distance / Time = 90 km / 1.5 h = 60 km/h. 2. A pendulum completes 30 oscillations in 45 seconds. Calculate its frequency. Frequency = Number of oscillations / Time = 30 / …
Numerical Questions and Solutions 1. A car is running at a speed of 60 km/h. How much time will it take to cover a distance of 27 km? Time = Distance / Speed = 27 km / 60 km/h = 0.45 hours or 27 minutes. 2. Reema observes her clock’s pendulum completes 15 oscillations in …
Numerical Questions and Solutions 1. A car is running at a speed of 60 km/h. How much time will it take to cover a distance of 27 km? Time = Distance / Speed = 27 km / 60 km/h = 0.45 hours or 27 minutes. 2. Reema observes her clock’s pendulum completes 15 oscillations in …
Solutions: Motion and Time – Grade VII Below are the solved questions from the Motion and Time assignment. Each answer is presented in detail for better understanding. Q1. Answer Briefly a. The distance-time graph of an object is a horizontal line parallel to the time axis when the object is at rest. Answer: When the …
Alternative Direct Substitution Approach Start from the given equation: [ costheta + sintheta = sqrt{2}costheta. ] Rearranging, we get: [ sintheta = (sqrt{2}-1)costheta. ] Now consider what we need to prove: [ costheta – sintheta = sqrt{2}sintheta. ] Substitute (sintheta = (sqrt{2}-1)costheta) into the left-hand side: [ costheta – sintheta = costheta – (sqrt{2}-1)costheta = …
Physics MCQs – Batch 1 & 2 1. What is thrust? Force exerted by an object in motion. Pressure applied by an object on a surface. Force exerted on a surface by an object, equal to its weight. (Correct) A gravitational pull experienced by objects on Earth. Correct Answer: Force exerted on a …
Physics Numericals Q1: Convert 1 mm of Hg into Pascal. (Take density of Hg = (13.6 times 10^3 , text{kg/m}^3) and ( g = 9.8 , text{m/s}^2 )). Solution:Given:Height of mercury column: ( h = 1 , text{mm} = 0.001 , text{m} )Density of mercury: ( rho = 13.6 times 10^3 , text{kg/m}^3 )Gravitational acceleration: …
“`html Physics Numericals Q11: (a) The diameter of neck and bottom of a bottle are 2 cm and 10 cm respectively. The bottle is completely filled with oil. If the cork in the neck is pressed in with a force of 1.2 kgf, what force is exerted on the bottom of the bottle? Solution: Given: …
“`html Physics Numericals Physics Numericals Q6: The pressure of water on the ground floor is 40,000 Pa, and on the first floor is 10,000 Pa. Find the height of the first floor. (Take: Density of water = (1000 , text{kg/m}^3), ( g = 10 , text{m/s}^2 )). Solution: Given: Pressure difference: ( Delta P = …
